Ten test tube mystery chegg

20.04.2021 By Zolokinos

You can only mix the solutions with each other. NH3 was easily identified by the smell. Flame colors can be used as well. Check the flame colours of all the other substances. The acids and bases will not give any colour.

The metals will give the following:. First, distinguish ammonia and NaOH. Mix the clear solutions with the Cu NO3 2 solution; a precipitate forms upon addition of base. If the base is ammonia, the precipitate will dissolve and form a very deep blue colour; if the base is NaOH, the precipitate will not dissolve. The solutions that give no flame colour Co, Mg, Al and Ag can be mixed with the basic solutions. NaOH and NH3 will precipitate them all. If they are mixed with acid, a few things can happen.

AgCl will precipitate if Ag is present and you mix it with HCl.

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This precipitate will dissolve in NH3. The yellow flames iron, sodium and calcium can be checked with acids as well.

Acid causes Na2CO3 to fizz, sulfuric acid precipitates Ca, and iron does not react with the acids. To work out which ones are the red flames, mix with acid.

Li does not react, Sr precipitates with H2SO4. The green flames, the same thing: acid. Nothing except mixing in the others. Take the NaOH you've now identified and add it to the various others. Two will give results. Take your 6M NaOH again and add it to the unidentified colourless solutions. Two will get quite hot because your neutralising 6M HCl and 3M sulphuric [use thermometer] To find out which acid is which, add portions of each to the three unidentified clear solns CaBa, and Bi.

Two may give white cloudy precipitates. The BiCl3 is the colourless one that did nothing with the HCl. This will go cloudy if diluted with water due to BiOCl.

Put equal amounts eg mL in a beaker. Add the 3M H2SO4 by means of a dropper, one drop at a time, and stirring. You've now Identified all. Tyler C. One is blue and the other is red. Answer Save. The metals will give the following: Ba: green Sr: red Li: red Zn: greenish, bright streaks in the flame Co: none, but bright streaks appear there may be some yellow due to Na contamination Mg: no change UV is emitted Na: bright yellow Al: none Cu: blue-green Fe: golden yellow K: lilac Ag: none Bunsen flames are not hot enough Ca: orange-yellow similar to, but darker than sodium Pb: blue-green The difference in flame colour will tell you whether you have iron or cobalt.

To distinguish between the different metals, try the following. This precipitate will not dissolve in NH3.Please join StudyMode to read the full document.

I need help with the Ten Test Tube Mystery?

The students were supposed to design a method in determining what chemical was in each test tube. The students are expected to determine the chemicals using physical properties, litmus paper, solubility, and the process of elimination.

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Physical properties, such as the color, can be determined by sight. Litmus paper can be determined through the change of color, if red then it is an acid, if blue then it is a base.

Solubility can be determined through reacting two chemicals together and see if a precipitate is created. Previous knowledge of the solubility rules will help disclose whether two chemicals will or will not create a precipitate. When two chemicals do create a precipitate, it will be easy to determine which chemicals they are.

In the end, one chemical will be left over.

ten test tube mystery chegg

Safety: Safety is always the first concern in a lab. Prior to the lab, students were asked to identify where the eye wash station was, the fire extinguisher and blanket were, and the safety shower was. When working with chemicals it is essential to wear safety glasses. Since the students were informed of which chemicals were going to be used prior to the experiment, the students should look at the Material Hubbard addressed her audience with an initial objective tone, revealing the built up to her credibility on the issue of in vitro fertilization.

Hubbard spoke at a time when in vitro fertilization was still a new developing technology as oppose to now. She spoke directly to society although at a certain point in her article; she focuses on a specific group of her readers.

Its central purpose is to cause awareness of the unforeseen dangers and consequences of in vitro fertilization and to take a clear stand on the use and the further development of the technology. In that sense, it may solve their particular infertility problems. Obtain a 30 cm length of bare copper wire, stirring rod, and 18 x mm test tube.

Coil the copper wire by wrapping it around a glass-stirring rod. Stretch the coiled wire until it is about 2 cm longer than the test tube. Leave wire tightly coiled near one end and stretched out and straighten toward the other. Weigh the wire and record it in the data table to the nearest 0. Using weigh paper, weigh out about 1. Record the measurement in data table to the nearest 0.

Caution: Be careful not to get any of the silver nitrate, solution or solid, on your skin or clothing. It will react with them.

Discovering the Mystery of Eleven Test Tubes

Measure about 20 mL of distilled water in a graduated cylinder and pour it into the test tube. Add the solid silver nitrate to the water in the test tube. Carefully move the stirring rod up and down to dissolve the crystals and mix the solution. Take great care not to poke a hole in the bottom of the test tube with the stirring rod.

Rinse the stirring rod with a small amount of distilled water into the test tube. Data that you collect will represent the heating and cooling behavior common to all pure substances.

Make a data table with headings for time, temperature of Paradichlorobenzene, and temperature of water.We use cookies to give you the best experience possible.

The students were handed 10 test tubes with no identification. The students were supposed to design a method in determining what chemical was in each test tube. The students are expected to determine the chemicals using physical properties, litmus paper, solubility, and the process of elimination. Physical properties, such as the color, can be determined by sight. Litmus paper can be determined through the change of color, if red then it is an acid, if blue then it is a base. Don't use plagiarized sources.

Previous knowledge of the solubility rules will help disclose whether two chemicals will or will not create a precipitate.

When two chemicals do create a precipitate, it will be easy to determine which chemicals they are. In the end, one chemical will be left over. Safety: Safety is always the first concern in a lab. Prior to the lab, students were asked to identify where the eye wash station was, the fire extinguisher and blanket were, and the safety shower was.

When working with chemicals it is essential to wear safety glasses. Since the students were informed of which chemicals were going to be used prior to the experiment, the students should look at the Material Safety Data Sheet to see what safety concerns may come with the chemicals being used.

ten test tube mystery chegg

In the experiment, the students worked with acids. To avoid spilling acids on their persons, the students used syringes to control where the acids were going to be placed.

Also, at the end of the experiment, students properly disposed of the laboratory waste and washed their hands, washing away any chemicals that they may have come in contact with.

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CuSO4 is blue. The litmus paper turned blue for the base and red for the acids. Pb NO3 2 and HCl creates a white precipitate. Pb NO3 2 and KI creates a yellow precipitate. NaBr is the remaining chemical.Then submit your finished lab report as a Microsoft Word document. This lab report is worth points towards your final lab grade. Each Q is worth 2 points unless otherwise noted. Also, per the Honor Code, this work must be your own. This is due Mon.

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Determining Unknown Solutions

The meat would not produce maggots as it was protected and Redi temporarily put to rest the notion of spontaneous generation. Chapter 4 describes how to use the latest version of Microsoft Access to create databases and extract data from databases. Chapter 5 continues the discussion of how to use Microsoft Access to develop database forms and reports. Part Three begins with Chapter….

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Essays Essays FlashCards. Browse Essays. Show More. Pb NO3 2 and HCl creates a white precipitate. Pb NO3 2 and KI creates a yellow precipitate.

ten test tube mystery chegg

NaBr is the remaining chemical. Results: 1. NaOH The only basic chemical found when it turned the litmus paper red. CuSO4 Identified by its natural blue color.We are not allowed to use any litmus paper and we need to discover which salt, acid, and base is contained in each tube.

Each of the 9 cations could react with each of the 5 anions in your tests, producing a total of 35 possible compounds. Therefore, list all of the possible combinations which could be insoluble solids or gasses, together with their colours:. But basically the procedure is to take a drop of 1 of the soloutions, and react it with each of the other But don't do them all at once; by doing the tests in a logical order, you can gradually identify many of the reagents without having to do all the tests.

Initially take a drop of just 1 soloution and react it with each of the other Take the NaOH you have now pointed out and upload it to the various others. Take your 6M NaOH returned and upload it to the unidentified colourless strategies. The BiCl3 is the colourless one that did no longer something with the HCl. No water, so upload the two the susceptible Ca NO3 2 orBa NO3 2 which ought to offer same result [as no hassle-free ion result]. Update: We are not allowed to use any litmus paper and we need to discover which salt, acid, and base is contained in each tube.

Update 2: We are not allowed to use any litmus paper and we need to discover which salt, acid, and base is contained in each tube. Answer Save. You appear to have 12 different soloutions, so why is it "10 test tube mystery"? These are only relevant if a precipitate or gas is formed. Also, it would be better if the soloutions were listed as A-M for clarity. Then do that for all 11 soloutions: a total of tests. Tests: Initially take a drop of just 1 soloution and react it with each of the other You can tell by the colour which is which.

So now you also know which is NaOH 8. Still have questions? Get your answers by asking now.Post a Comment. This experiment was harder to set up for than it was to actually do. So, we were given 10 different solutions.

I need help with the Ten Test Tube Mystery?

So our goal was to find the other 7 through a series of tests. First we had to create a reaction table. That is, we set up a ten by ten table, and indicated the reaction between each of the 10 solutions. We also knew that all of our bases and our acids would create heat, with no precipitate.

This was my groups set of chemicals. This was the other set, I have no idea what they are. We had to determine the solutions with at least five steps. This was my thought process, but we discussed everything as a group. First, I wrote down what each of the three solutions that we knew were by direct observation. Then I wrote down what each of the solutions reacted with.

The nickel nitrate and the copper nitrate only reacted with sodium hydroxide and ammonium hydroxide. We decided to test with copper nitrate. Since we also already knew the identity of ammonium hydroxide and nickel nitrate, we only needed to test the other 7 solutions. We added each unknown solution into it's own test tube, then added a little copper nitrate to each and looked for a precipitate.

What was interesting is that the precipitate took all the blue out of the solution! Really cool looking. Here's my really bad paint example.YOu can only mix the test tubes. They will not be color dyed. You must be able to tell what is in each tube. You're looking for precipitates, or color changes. Use a grid to chart what reacts with what. In your case a 4 by 6 grid. Study the reactions of each.

That means writing 24 equations. Some will react some will not. Focus on ones that will form visual changes or precipitates and use logic and deduction to figure out what is what.

Have fun! Nothing except mixing in the others. Take the NaOH you've now identified and add it to the various others.

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Two will give results. Take your 6M NaOH again and add it to the unidentified colourless solutions. Two will get quite hot because your neutralising 6M HCl and 3M sulphuric [use thermometer]. To find out which acid is which, add portions of each to the three unidentified clear solns CaBa, and Bi. Two may give white cloudy precipitates. The BiCl3 is the colourless one that did nothing with the HCl. This will go cloudy if diluted with water due to BiOCl.

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Put equal amounts eg mL in a beaker. Add the 3M H2SO4 by means of a dropper, one drop at a time, and stirring. Take the NaOH you have now pointed out and upload it to the numerous others. Take your 6M NaOH lower back and upload it to the unidentified colourless strategies. The BiCl3 is the colourless one which failed to something with the HCl. No water, so upload the two the vulnerable Ca NO3 2 orBa NO3 2 which ought to provide comparable effect [as no straight forward ion effect].